homework help 968

The volume of ice would be ##”1091 cm”^3##.

The of water at 0 °C is ##”0.9998 g/cm”^3##.

If you had 1 L of water at that temperature, its mass would be

##M = 1000 color(red)(cancel(color(black)(“cm”^3))) × “0.9998 g”/(1color(red)(cancel(color(black)(“cm”^3)))) = “999.8 g”##

The density of ice at 0 °C is ##”0.9162 g/cm”^3##.

The volume of 998.8 g of ice at 0 °C is

##V = 998.8 color(red)(cancel(color(black)(“g”))) × (“1 cm”^3)/(0.9162 color(red)(cancel(color(black)(“g”))))= “1091 cm”^3##