homework help 1993

##5##

Question: ##sqrt(125/5)##

For this question, you need to know the following formulas:

1. ##sqrt(a/b) = sqrta/sqrtb##

2. ##sqrt(axxb) = sqrta xx sqrt b##

##sqrt(125/5) = sqrt125/sqrt5## ——————– ##sqrt(a/b) = sqrta/sqrtb##

##= sqrt(25xx5)/sqrt5## —————– ##sqrt(axxb)##

##= (sqrt25xxsqrt5)/sqrt5## ————– ##sqrta xx sqrt b##

##= (5xxsqrt5)/sqrt5##

##= (5sqrt5)/sqrt5##

##= (5cancelsqrt5)/cancelsqrt5##

##= 5##

##:. Ans: 5##