homework help 1734

##F=68##

##C_f:” the freezing point of pure water in Celsius scale “##
##C_b:” the boiling point of pure water in Celsius scale”##

##F_f:” the freezing point of pure water in Fahrenheit scale”##
##F_b:” the boiling point of pure water in Fahrenheit scale”##

##C_f=0″ ; “C_b=100##
##F_f=32” ; “F_b=212##

##(C-C_f)/(C_b-C_f)=(F-F_f)/(F_b-F_f)##

##(20-0)/100=(F-32)/180##

##20/100=(F-32)/(180)##

##1/5=(F-32)/180##

##cancel(180)=cancel(5)(F-32)##

##36=F-32##

##F=36+32##

##F=68##