homework help 1341

##2Ag_2O-> 4Ag + O_2##

How to balance?
We have an equation;
##Ag_2O -> Ag + O_2##
First of all balance the O on both sides, now look at the product side. We have 2 oxygen on right side and on left side we have only 1 oxygen. To balance it, put a coefficient 2 on left side before ##Ag_2O## . The equation becomes as
##2Ag_2O -> Ag + O_2##
Now again check the product side, There is 1 Ag but in reactant side there is 4 Ag. Now put coefficient 4 before Ag on right side. The equation becomes as;
##2Ag_2O-> 4Ag + O_2##

Solution:

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