whatsapp us on +1(786)6864430 or ±1(786)6738197

homework help 1256

is defined as ##J//(K*kg) or J*K^-1*kg^-1##
(=energy per degree per kilogram of mass)

So you just divide heat capacity of the object by the mass:

##c_”silver”=(42.8J//K)/(0.181kg)~~236J/(K*kg)##

Extra :
Officially, specific heat is defined as the amount of energy needed to raise the temperature of ##1kg## by ##1K##. Since a temperature difference of ##1K## is equal to one of ##1^oC## this is no problem.
Since the SI-unit of mass is ##kg## in stead of ##g## the official answer should be: ##236J//(K*kg)## or ##236J*K^-1*kg^-1##
But most people use the earlier notation of ##J//g*^oC##
which will turn out to be ##0.236J//g*^oC##

Solution:

15% off for this assignment.

Our Prices Start at $11.99. As Our First Client, Use Coupon Code GET15 to claim 15% Discount This Month!!

Why US?

100% Confidentiality

Information about customers is confidential and never disclosed to third parties.

Timely Delivery

No missed deadlines – 97% of assignments are completed in time.

Original Writing

We complete all papers from scratch. You can get a plagiarism report.

Money Back

If you are convinced that our writer has not followed your requirements, feel free to ask for a refund.